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Probability problem

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楼主

发表于 2004-11-5 08:27:42 | 显示全部楼层

P = 1 - P(365,50)/365^50 = 1 - 365!/315!/365^50 = 1 - 0.029626 = 0.970374

P(365,50) is the permutation of all possible ways to distribute 50 b-days. (no repeat)

365^50 represent all possible ways of arranging 50 bdays.

and you will get the probability of more than 1 ppl has the same bday. then subtracted by 1, u will get the answer :D

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沙发

发表于 2004-11-8 02:29:02 | 显示全部楼层

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