珍珠湾ART

标题: Probability problem [打印本页]

作者: ob    时间: 2004-11-4 22:59
标题: Probability problem

What are the chances that at least two out of a group of fifty people share the same birthday?
www.ddhw.com

 

作者: ac_x    时间: 2004-11-5 08:27
标题: 回复:Probability problem

P = 1 - P(365,50)/365^50 = 1 - 365!/315!/365^50 = 1 - 0.029626 = 0.970374
 
P(365,50) is the permutation of all possible ways to distribute 50 b-days. (no repeat)
365^50 represent all possible ways of arranging 50 bdays.
and you will get the probability of more than 1 ppl has the same bday. then subtracted by 1, u will get the answer :D
www.ddhw.com

 

作者: sean9991    时间: 2004-11-5 18:15
标题: 回复:回复:Probability problem

you forgot if somebody was born in leap year, then his birthday is Feb 29.  And the probability of a random people has this birthday is approximately 97/400 of other days.
www.ddhw.com

 

作者: ac_x    时间: 2004-11-8 02:29
标题: answer is above

  answer is above









欢迎光临 珍珠湾ART (http://www.zzwav.com/) Powered by Discuz! X3