Infinitely many: |x+1|+|x-1|=2. Obviously, [-1, 1] is the solution set.www.ddhw.com Three solutions: Well, I do not have one example. Actually I do not think we can have one. Cause f(x)=|ax+b|+|cx+d|+...+|mx+n| is convex..... Therefore, if there are only a finite number of solutions, then there are 2, 1, or zero solutions. Need to check again though. www.ddhw.com
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